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प्रश्न
The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.
Based upon the above information, solve the questions given below:
Which of the following orbitals has the lowest energy?
4d, 4f, 5s, 5p
उत्तर
| Orbitals | n | n + l |
| 4d | 4 | 6 |
| 4f | 4 | 7 |
| 5s | 5 | 5 |
| 5p | 5 | 6 |
The lowest energy orbital is 5s
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संबंधित प्रश्न
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X = 6, 1, −1, `+1/2`
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