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The correct increasing order of the oxidation state of sulphur in the anions SOX42−,SOX32−,SX2OX42−,SX2OX62− is - Chemistry

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प्रश्न

The correct increasing order of the oxidation state of sulphur in the anions \[\ce{SO^2-_4, SO^2-_3, S2O^2-_4, S2O^2-_6}\] is

पर्याय

  • \[\ce{SO^2-_3 < SO^2-_4 < S2O^2-_4 < S2O^2-_6}\]

  • \[\ce{SO^2-_4 < S2O^2-_4 < S2O^2-_6 < SO^2-_3}\]

  • \[\ce{S2O^2-_4 < SO^2-_3 < S2O^2-_6 < SO^2-_4}\]

  • \[\ce{S2O^2-_6 < S2O^2-_4 < SO^2-_4 < SO^2-_3}\]

MCQ

उत्तर

\[\ce{S2O^2-_4 < SO^2-_3 < S2O^2-_6 < SO^2-_4}\]

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पाठ 1: Basic Concepts of Chemistry and Chemical Calculations - Evaluation [पृष्ठ ३१]

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सामाचीर कलवी Chemistry - Volume 1 and 2 [English] Class 11 TN Board
पाठ 1 Basic Concepts of Chemistry and Chemical Calculations
Evaluation | Q I. 16. | पृष्ठ ३१
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