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Balance the following equation by the oxidation number method. KX2CrX2OX7+Kl+HX2SOX4⟶KX2SOX4+CrX2(SOX4)X3+IX2+HX2O - Chemistry

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प्रश्न

Balance the following equation by the oxidation number method.

\[\ce{K2Cr2O7 + Kl + H2SO4 -> K2SO4 + Cr2(SO4)3 + I2 + H2O}\]

थोडक्यात उत्तर

उत्तर

\[\ce{K2Cr2O7 + 6Kl + H2SO4 -> K2SO4 + Cr2(SO4)3 + I2 + H2O}\]

\[\ce{K2Cr2O7 + 6Kl + H2SO4 -> K2SO4 + Cr2(SO4)3 + 3I2 + H2O}\]

\[\ce{K2Cr2O7 + 6Kl + 7H2SO4 -> 4K2SO4 + Cr2(SO4)3 + 3I2 + 7H2O}\]

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पाठ 1: Basic Concepts of Chemistry and Chemical Calculations - Evaluation [पृष्ठ ३५]

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सामाचीर कलवी Chemistry - Volume 1 and 2 [English] Class 11 TN Board
पाठ 1 Basic Concepts of Chemistry and Chemical Calculations
Evaluation | Q II. 18) i) | पृष्ठ ३५
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