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Tamil Nadu Board of Secondary EducationHSC Science Class 11

Balance the following equation by the oxidation number method. KX2CrX2OX7+Kl+HX2SOX4⟶KX2SOX4+CrX2(SOX4)X3+IX2+HX2O - Chemistry

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Question

Balance the following equation by the oxidation number method.

\[\ce{K2Cr2O7 + Kl + H2SO4 -> K2SO4 + Cr2(SO4)3 + I2 + H2O}\]

Answer in Brief

Solution

\[\ce{K2Cr2O7 + 6Kl + H2SO4 -> K2SO4 + Cr2(SO4)3 + I2 + H2O}\]

\[\ce{K2Cr2O7 + 6Kl + H2SO4 -> K2SO4 + Cr2(SO4)3 + 3I2 + H2O}\]

\[\ce{K2Cr2O7 + 6Kl + 7H2SO4 -> 4K2SO4 + Cr2(SO4)3 + 3I2 + 7H2O}\]

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Chapter 1: Basic Concepts of Chemistry and Chemical Calculations - Evaluation [Page 35]

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Samacheer Kalvi Chemistry - Volume 1 and 2 [English] Class 11 TN Board
Chapter 1 Basic Concepts of Chemistry and Chemical Calculations
Evaluation | Q II. 18) i) | Page 35
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