Advertisements
Advertisements
Question
Total number of electrons present in 1.7 g of ammonia is
Options
6.022 × 1023
`(6.022 xx 10^22)/1.7`
`(6.022 xx 10^24)/1.7`
`(6.022 xx 10^23)/1.7`
Solution
6.022 × 1023
Explanation:
No. of electrons present in one ammonia (NH3) molecule (7 + 3) = 10
No. of moles of ammonia = `"Mass"/"Molar mass"`
= `(1.7 "g")/(17 "gmol"^-1)`
= 0.1 mol
No. of molecules present in 0.1 mol of ammonia
= 0.1 × 6.022 × 1023
= 6.022 × 1022
No. of electrons present in 0.1 mol of ammonia
= 10 × 6.022 × 1022
= 6.022 × 1023
APPEARS IN
RELATED QUESTIONS
Which of the following contains the same number of carbon atoms as in 6 g of carbon-12.
What do you understand by the term oxidation number?
Balance the following equation by the oxidation number method.
\[\ce{K2Cr2O7 + Kl + H2SO4 -> K2SO4 + Cr2(SO4)3 + I2 + H2O}\]
Balance the following equation by the oxidation number method.
\[\ce{Cu + HNO3 -> Cu(NO3)2 + NO2 + H2O}\]
Balance the following equation by the oxidation number method.
\[\ce{KMnO4 + H2C2O4 + H2SO4 -> K2SO4 + MnSO4 + CO2 + H2O}\]
Reducing agent is a species that ____________.
What is the formula of hydrolith?
In the redox reaction, \[\ce{2MnO^-_4 + SO^{2-}_3 + H2O -> 2MnO^{2-}_4 + SO^{2-}_4 + 2H^+}\], the reductant is:
Which one of the following CANNOT act as a reducing agent?
Which of the following represents a redox reaction?
