Advertisements
Advertisements
प्रश्न
The daily maximum relative humidity (in percent) in Mumbai from May 1 to May 7, 1992 is given below: 64, 70, 65, 80, 75, 78
Find the mean.
उत्तर
Data: 64, 70, 65, 80, 75, 78
Total number of observation = n = 6
Mean = `"Sum of observations"/"Total number of observations"`
= `(64 + 70 + 65 + 80 + 75 + 78)/(6)`
= 72.
APPEARS IN
संबंधित प्रश्न
Find the mean of x + 3, x + 5, x + 7, x + 9 and x + 11.
The mean of 15 observations is 32. Find the resulting mean, if the observation is: Increased by 60%
Find the mean of 8, 12, 16, 22, 10 and 4. Find the resulting mean, if the observations, given above, be: multiplied by 3 and then divided by 2.
Find the mean of 8, 12, 16, 22, 10 and 4. Find the resulting mean, if each of the observations, given above, be: increased by 25%
Find the mean of 8, 12, 16, 22, 10 and 4. Find the resulting mean, if each of the observations, given above, be: decreased by 40%
Find the mean of the following data: 30, 32, 24, 34, 26, 28, 30, 35, 33, 25
(i) Show that the sum of the deviations of all the given observations from the mean is zero.
(ii) Find the median of the given data.
Individual scores of a school cricket eleven in a match are given below:
10, 9, 31, 45, 0, 4, 8, 15, 12, 0, 6
Find the average score.
The mean of 16 natural numbers is 48. Find the resulting mean, if each of the number is increased by 5
The mean of 16 natural numbers is 48. Find the resulting mean, if each of the number is divided by 0.25
The mean of 16 natural numbers is 48. Find the resulting mean, if each of the number is increased by 50%