Advertisements
Advertisements
प्रश्न
The marks obtained by 10 students are listed below:
2, 5, 3, 8, 0, 9, x, 6, 1, 8
If the mean marks is 5, find x.
उत्तर
Mean = `(sumx)/"N"`
= `(2 + 5 + 3 + 8 + 0 + 9 + x + 6 + 1 + 8)/(10)`
= `(42 + x)/(10)`
∴ 5 = `(42 + x)/(10)`
⇒ 50 = 42 + x
⇒ x = 50 - 42 = 8.
APPEARS IN
संबंधित प्रश्न
Find the mean of x + 3, x + 5, x + 7, x + 9 and x + 11.
The mean weight of 60 students in a class is 40 kg. The mean weight of boys is 50 kg while that of girls is 30 kg. Find the number of boys and girls in the class.
The mean of x, x + 2, x + 4, x + 6 and x + 8 is 11, find the mean of the first three observations.
Find the mean and median of the data: 35, 48, 92, 76, 64, 52, 51, 63 and 71.
If 51 is replaced by 66, what will be the new median?
Find the mean of the following data: 30, 32, 24, 34, 26, 28, 30, 35, 33, 25
(i) Show that the sum of the deviations of all the given observations from the mean is zero.
(ii) Find the median of the given data.
A boy scored the following marks in various class tests during a terminal exam, each test being marked out of 20.
17, 15, 16, 7, 10, 14, 12, 19, 16, 12
Find his average mean marks.
The daily maximum relative humidity (in percent) in Mumbai from May 1 to May 7, 1992 is given below: 64, 70, 65, 80, 75, 78
Find the mean.
If the mean of 7, 16, 9, 15, 16, a, 12, 8, b, 11 is 12, write a in terms of b.
In History project, marks out of 20 were awarded to 8 students. The marks were as shown below: 14, 16, 18, 14, 16, 14, 12, 16
Each of the above students was 2 extra marks for submitting the project a week before the due date. What is the revised mean of this group?
The mean of 16 natural numbers is 48. Find the resulting mean, if each of the number is decreased by 8
