Advertisements
Advertisements
Question
The daily maximum relative humidity (in percent) in Mumbai from May 1 to May 7, 1992 is given below: 64, 70, 65, 80, 75, 78
Find the mean.
Solution
Data: 64, 70, 65, 80, 75, 78
Total number of observation = n = 6
Mean = `"Sum of observations"/"Total number of observations"`
= `(64 + 70 + 65 + 80 + 75 + 78)/(6)`
= 72.
APPEARS IN
RELATED QUESTIONS
The mean of 15 observations is 32. Find the resulting mean, if the observation is: Decreased by 7
The mean of 15 observations is 32. Find the resulting mean, if each observation is: Multiplied by 2
Find the mean of 8, 12, 16, 22, 10 and 4. Find the resulting mean, if the observations, given above, be: multiplied by 3.
The mean of 15 observations is 32. Find the resulting mean, if the observation is: Decreased by 20%
Find the mean of 8, 12, 16, 22, 10 and 4. Find the resulting mean, if each of the observations, given above, be: decreased by 40%
The mean weight of 60 students in a class is 40 kg. The mean weight of boys is 50 kg while that of girls is 30 kg. Find the number of boys and girls in the class.
The height of 8 students X in centimetres are given below:
148, 162, 160, 154, 170, 162, x, 152
If the mean height is 158, find x.
A test out of 25 marks was given to 16 students and marks scored are recorded below: 25, 8, 14, 20, 16, 22, 10, 15, 8, 7, 24, 18, 19, 6, 11, 14
In the report, marks were entered out of 50. What is the mean of the recorded marks in the report?
The mean of 16 natural numbers is 48. Find the resulting mean, if each of the number is increased by 5
The mean of 4 observations is 20. If one observation is excluded, the mean of the remaining observations becomes 15. Find the excluded observation.
