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प्रश्न
The diameters of the ends of a frustum of a cone are 32 cm and 20 cm. If its slant height is 10 cm, then its lateral surface area is
पर्याय
321 π cm2
300 π cm2
260 π cm2
250 π cm2
उत्तर
`r_1 = 32/2`
`= 16 "cm"`
`r_2 = 20/2`
` = 10 cm`
Slant height = 10 cm
Total lateral surface area
`= pi(r_1 +r_2) l`
`=pi (16 + 10 )10`
= 260 \[\pi {cm}^2\]
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Find the total surface area of frustum, if its radii are 15 cm and 7 cm. Also, the slant height of the frustum is 14 cm.
Radii of the frustum = `square` cm and `square` cm
Slant height of the frustum = `square` cm
Total surface area = `π[(r_1^2 + r_2^2 + (r_1 + r_2)l]`
= `22/7 [square + square + (square + square) square]`
= `22/7 (square)`
= `square` cm2
Hence, the total surface area of the frustum is `square`.
