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Question
The diameters of the ends of a frustum of a cone are 32 cm and 20 cm. If its slant height is 10 cm, then its lateral surface area is
Options
321 π cm2
300 π cm2
260 π cm2
250 π cm2
Solution
`r_1 = 32/2`
`= 16 "cm"`
`r_2 = 20/2`
` = 10 cm`
Slant height = 10 cm
Total lateral surface area
`= pi(r_1 +r_2) l`
`=pi (16 + 10 )10`
= 260 \[\pi {cm}^2\]
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