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Question
A reservoir is in the shape of a frustum of a right circular cone. It is 8 m across at the top and 4 m across at the bottom. If it is 6 m deep, then its capacity is
Options
176 m3
196 m3
200 m3
110 m3
Solution
`r_1 = 8/2`
`= 4m`
`r_2 = (4m)/alpha`
`= 2m and`
`h = 6m`
The volume of reservoir
`=h/3pi {r_1^2 + r_2^2 + r_1 r_2}`
`=6/3 pi[16 +4 + 8]`
`=56 pi`
`= 56 xx 22/7`
`=176 m^2`
The volume of reservoir = 176 m2
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