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Question
A drinking glass is in the shape of the frustum of a cone of height 21 cm with 6 cm and 4 cm as the diameters of its two circular ends. Find the capacity of the glass.
Solution
Let R and r be the radii of the top and base, respectively, of the drinking glass and let its height be h.
Then, `R => 6/2 "cm" = 3 "cm", "r" => 4/2 "cm" = 2 "cm", h=21 "cm" `
Capacity of the glass = Capacity of the frustum of the cone
`=(pi"h")/3["R"^2+"r"^2+"Rr"]`
`=22/7xx1/3xx21xx[(3)^2+(2)^2+(3xx2)]"cm"^3`
= (22 × 19) cm3
= 418 cm3
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