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Question
A bucket of height 24 cm is in the form of frustum of a cone whose circular ends are of diameter 28 cm and 42 cm. Find the cost of milk at the rate of ₹30 per litre, which the bucket can hold.
Solution
We have,
Height of the frustum, h = 24 cm and
Radius of the open end, `"R" = 42/2 = 21 "cm" and`
Radius of the close end, `"R" = 28/2 = 14 "cm"`
Now,
volume of the bucket `= 1/3 pi"h"("R"^2+"r"^2 + "Rr")`
`=1/3xx22/7xx24xx(21^2+14^2+21xx14)`
`=176/7xx(441+196+294)`
`=176/7xx931`
= 23408 cm3
= 23.408 L (As, 1000 cm3 = 1 L)
∴ The cost of the milk which the bucket can hold is ₹ 702.24
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