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Question
The maximum volume of a cone that can be carved out of a solid hemisphere of radius r is
Options
\[3 \pi r^2\]
- `1/3pir^3`
\[\frac{\pi r^2}{3}\]
\[3 \pi r^3\]
Solution
Radius of hemisphere = r
Therefore,
The radius of cone = r
and height h = r
Then,
Volume of cone
`=1/3 pir^2 h `
`=1/3pir^2 xx r`
`=1/3 pir^3 ("unit")^3`
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