Advertisements
Advertisements
प्रश्न
The difference between two positive numbers is 4 and the difference between their cubes is 316.
Find : Their product
उत्तर
Given difference between two positive numbers is 4 and difference between their cubes is 316.
Let the positive numbers be a and b
a - b = 4
a3 - b3 = 316
Cubing both sides,
(a - b)3 = 64
a3 - b3 - 3ab(a - b) = 64
Given a3 - b3 = 316
So 316 - 64 = 3ab(4)
252 = 12ab
So ab = 21; product of numbers is 21
APPEARS IN
संबंधित प्रश्न
Expand : ( x - 8 )( x - 10 )
Expand : `( 2x - 1/x )( 3x + 2/x )`
If x > 0 and `x^2 + 1/[9x^2] = 25/36, "Find" x^3 + 1/[27x^3]`
If a2 + b2 = 34 and ab = 12; find : 3(a + b)2 + 5(a - b)2
If a2 + b2 = 34 and ab = 12; find : 7(a - b)2 - 2(a + b)2
If x2 + `x^(1/2)`= 7 and x ≠ 0; find the value of :
7x3 + 8x - `7/x^3 - 8/x`
Find the value of 'a': 4x2 + ax + 9 = (2x + 3)2
Find the value of 'a': 4x2 + ax + 9 = (2x - 3)2
Find the value of 'a': 9x2 + (7a - 5)x + 25 = (3x + 5)2
If 3a + 5b + 4c = 0, show that : 27a3 + 125b3 + 64c3 = 180 abc