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प्रश्न
The energy of a photon of wavelength λ is ______.
पर्याय
hc λ
`(hc)/lambda`
`lambda/(hc)`
`(lambdah)/c`
उत्तर
The energy of a photon of wavelength λ is `underlinebb((hc)/lambda)`.
Explanation:
The energy of a photon is given by,
E = hν
h = Planck's constant, ν (frequency) = `c/lambda`
So, `E = (hc)/lambda`
संबंधित प्रश्न
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