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Question
The energy of a photon of wavelength λ is ______.
Options
hc λ
`(hc)/lambda`
`lambda/(hc)`
`(lambdah)/c`
Solution
The energy of a photon of wavelength λ is `underlinebb((hc)/lambda)`.
Explanation:
The energy of a photon is given by,
E = hν
h = Planck's constant, ν (frequency) = `c/lambda`
So, `E = (hc)/lambda`
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