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प्रश्न
The function ‘t’ which map temperature in Celsius (C) into temperature in Fahrenheit (F) is defined by t(C) = F where F = `9/5` C + 32. Find, the value of C when t(C) = 212
उत्तर
Given t(C) = `9/5` C + 32
t(C) = 212
`9/5` C + 32 = 212
`9/5` C = 212 – 32
= 180
9C = 180 × 5
C = `(180 xx 5)/9`
= 100° C
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