Advertisements
Advertisements
प्रश्न
The given figure shows a right-angled triangle ABC and an equilateral triangle BCD. Find the area of the shaded portion.
उत्तर
From ΔABC,
AB = `sqrt("AC"^2 - "BC"^2)`
= `sqrt( 16^2 - 8^2)`
= `sqrt192`
Area of ΔABC
ΔABC = `1/2 xx 8 xx sqrt192`
= `4 sqrt192`
Area of ΔBCD
ΔBCD = `sqrt3/4 xx 8^2`
= `16 sqrt3`
Now
ABD = ABC - BDC
= `4sqrt192 - 16sqrt3`
= `32sqrt3 - 16sqrt3`
= `16sqrt3` sq.cm
APPEARS IN
संबंधित प्रश्न
Find the area of a triangle whose sides are 18 cm, 24 cm, and 30 cm. Also, find the length of altitude corresponding to the largest side of the triangle.
If the difference between the sides of a right-angled triangle is 3 cm and its area is 54 cm2; find its perimeter.
In triangle ABC; angle A = 90o, side AB = x cm, AC = (x + 5) cm and area = 150 cm2. Find the sides of the triangle.
Find the area of a triangle, whose sides are :
18 mm, 24 mm and 30 mm
Find the area of a triangle, whose sides are :
21 m, 28 m, and 35 m
Find the area of a right angled triangle whose hypotenuse is 15cm and the base is 9cm.
Find the area of a triangle with a base 12cm and a height equal to the width of a rectangle having area of 96cm2 and a length of 12cm.
Find the perimeter and the area of a right angled triangle whose sides are 6 feet, 8 feet and 10 feet
From one vertex of an equilateral triangle with side 40 cm, an equilateral triangle with 6 cm side is removed. What is the perimeter of the remaining portion?
Area of an isosceles triangle is 48 cm2. If the altitudes corresponding to the base of the triangle is 8 cm, find the perimeter of the triangle.
