Advertisements
Advertisements
प्रश्न
Find the area of a triangle whose sides are 18 cm, 24 cm, and 30 cm. Also, find the length of altitude corresponding to the largest side of the triangle.
उत्तर
Since the sides of the triangle are 18 cm, 24 cm and 30 cm respectively.
s = `(18 + 24 + 30)/(2)`
= 36
Hence the area of the triangle is
A = `sqrt (s( s - a ) ( s - b ) (s -c ))`
= `sqrt (36( 36 - 18 ) ( 36 - 24 ) (36 -30 ))`
= `sqrt (36 xx 18 xx 12 xx 6 )`
= ` sqrt ( 46656 ) `
= 216 sq.cm.
Again
A = `1/2 "base" xx "altitude" `
Hence
216 = `1/2 xx 30 xx h`
h = 14.4cm
APPEARS IN
संबंधित प्रश्न
AD is altitude of an isosceles triangle ABC in which AB = AC = 30 cm and BC = 36 cm. A point O is marked on AD in such a way that ∠BOC = 90o. Find the area of quadrilateral ABOC.
In triangle ABC; angle A = 90o, side AB = x cm, AC = (x + 5) cm and area = 150 cm2. Find the sides of the triangle.
The area of an equilateral triangle is 36`sqrt3` sq. cm. Find its perimeter.
Find the area and the perimeter of quadrilateral ABCD, given below; if AB = 8 cm, AD = 10 cm, BD = 12 cm, DC = 13 cm and ∠DBC = 90°.
Find the area of a triangle with a base 12cm and a height equal to the width of a rectangle having area of 96cm2 and a length of 12cm.
Find the area of a triangle with a base 12cm and a height equal to the width of a rectangle having area of 96cm2 and a length of 12cm.
Find the perimeter of the triangle, whose sides are 13 cm, 5 cm and 14 cm
The perimeter of a triangle is 28 cm. One of it’s sides is 8cm. Write all the sides of the possible isosceles triangles with these measurements.
Find the perimeter of a triangle with sides measuring 10 cm, 14 cm and 15 cm.
A piece of string is 30 cm long. What will be the length of each side if the string is used to form an equilateral triangle?
