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प्रश्न
The graphs below show the variation of the stopping potential VS with the frequency (ν) of the incident radiations for two different photosensitive materials M1 and M2.
Express work function for M1 and M2 in terms of Planck’s constant(h) and Threshold frequency and charge of the electron (e).
If the values of stopping potential for M1 and M2 are V1 and V2 respectively then show that the slope of the lines equals to `(V_1-V_2)/(V_(01)-V_(02))` for a frequency,
ν > ν02 and also ν > ν01
उत्तर
`"W"_(01) = ("h"ν_(01))/"e" and "W"_(02) = ("h"ν_(02))/"e"`
`"V"_1 = ["h"/"e"] ν-["h"/"e"]"V"_01`
`"V"_2 = ["h"/"e"]ν-["h"/"e"]"V"_(02)`
∴ `"V"1 - "V"2 = ["h"/"e"]("V"_(01)-"V"_(02))`
`["h"/"e"] = ("V"1-"V"2)/("V"_(01)-"V"_(02))`
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