Advertisements
Advertisements
प्रश्न
The hypotenuse of a right=-angled triangle is 20 meters. If the difference between the lengths of the other sides be 4 meters, find the other sides
उत्तर
Let one side of the right-angled triangle be x m and the other side be `(x+4)m` On applying Pythagoras theorem, we have:
`20^2=(x+4)^2+x^2`
⇒` 400x^2+8x+16+x^2`
⇒ `2x^2+8x-384=0`
⇒`x^2+4x-192=0`
⇒`x^2+16x-12x-192=0`
⇒ `x^2(x+16) -12(x+16)=0`
⇒`(x+16) (x-12)=0`
⇒` x=-16 or x=12`
The value of x cannot be negative.
Therefore, the base is 12 m and the other side is `{(12+4)=16m}`
APPEARS IN
संबंधित प्रश्न
Two water taps together can fill a tank in `9 3/8`hours. The tap of larger diameter takes 10 hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank.
A farmer prepares rectangular vegetable garden of area 180 sq meters. With 39 meters of barbed wire, he can fence the three sides of the garden, leaving one of the longer sides unfenced. Find the dimensions of the garden.
Solve the following quadratic equation by completing the square method.
2y2 + 9y + 10 = 0
Solve the following quadratic equation by completing the square method.
5x2 = 4x + 7
Form the quadratic equation from the roots given below.
\[2 - \sqrt{5}, 2 + \sqrt{5}\]
Sum of the area of two squares is 400 cm2. If the difference of their perimeters is 16 cm, find the sides of two squares.
The value of \[\sqrt{6 + \sqrt{6 + \sqrt{6 +}}} . . . .\] is
One year ago, a man was 8 times as old as his son. Now his age is equal to the square of his son’s age. Their present ages are:
Rohini had scored 10 more marks in her mathematics test out of 30 marks, 9 times these marks would have been the square of her actual marks. How many marks did she get on the test?
Find the value of x, if 3x – 7 × 4x – 4 = 768.
