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प्रश्न
The latus-rectum of the hyperbola 16x2 − 9y2 = 144 is
पर्याय
16/3
32/3
8/3
4/3
उत्तर
32/3
The standard form of the hyperbola \[16 x^2 - 9 y^2 = 144\] is \[\frac{x^2}{9} - \frac{y^2}{16} = 1\].
Here,
\[a^2 = 9, b^2 = 16\]
Latus rectum of the hyperbola = \[\frac{2 b^2}{a} = \frac{2 \times 16}{3} = \frac{32}{3}\]
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