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प्रश्न
The median first 6 odd natural numbers is ____________
पर्याय
6
7
8
14
उत्तर
6
Explanation;
Hint: 1, 3, 5, 7, 9, 11
Medain = `(5 + 7)/2`
= `12/2`
= 6
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संबंधित प्रश्न
The following distribution represents the height of 160 students of a school.
Height (in cm) | No. of Students |
140 – 145 | 12 |
145 – 150 | 20 |
150 – 155 | 30 |
155 – 160 | 38 |
160 – 165 | 24 |
165 – 170 | 16 |
170 – 175 | 12 |
175 – 180 | 8 |
Draw an ogive for the given distribution taking 2 cm = 5 cm of height on one axis and 2 cm = 20 students on the other axis. Using the graph, determine:
- The median height.
- The interquartile range.
- The number of students whose height is above 172 cm.
Marks obtained (in mathematics) by 9 student are given below:
60, 67, 52, 76, 50, 51, 74, 45 and 56
if marks of each student be increased by 4; what will be the new value of arithmetic mean.
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Class | 1-10 | 11-20 | 21-30 | 31-40 | 41-50 | 51-60 | 61-70 |
Frequency | 7 | 10 | 14 | 17 | 15 | 11 | 6 |
Find the median of the following:
3x, x+5, x+7, x+9, x+11, x+13
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Marks% | 10-19 | 20-29 | 30-39 | 40-49 | 50-59 | 60-69 | 70-79 | 80-89 |
No. of Students | 7 | 11 | 20 | 46 | 57 | 37 | 15 | 7 |
Draw an ogive and find the number of students who scored more than 35% marks
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