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The probability density function of X is given byeforforf(x)={ke-x3for x>00for x≤0Find the distribution function - Mathematics

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प्रश्न

The probability density function of X is given by
`f(x) = {(k"e"^(- x/3), "for"  x > 0),(0,"for"  x ≤ 0):}`
Find the distribution function

बेरीज

उत्तर

The distribution function F(x) = `int_-oo^x f(u) "d"u`

Case 1: 

x < 0, F(x) = `int_-oo^x f(u)  "d"u` = 0

Case 2: 

x ≥ 0,  F(x) = `int_-oo^x f(u)  "d"u`

= `int_-oo^0 f(u)  "d"u + int_0^x f(u)  "d"u`

= `0 + k int_0^x "e"^((-u)/3)  "d"u`

= `1/3 [("e"^((-u)/3))/((-1)/3)]_0^x`

= `- ("e"^((-x)/3) - 1)`

= `1 - "e"^((- x)/3)`

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Continuous Distributions
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 11: Probability Distributions - Exercise 11.3 [पृष्ठ २०२]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
पाठ 11 Probability Distributions
Exercise 11.3 | Q 4. (ii) | पृष्ठ २०२

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