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प्रश्न
The radii of the circular ends of a solid frustum of a cone are 33 cm and 27 cm and its slant height is 10 cm. Find its total surface area. [Use π = 3.14.]
उत्तर
Greater radius = R = 33 cm
Smaller radius = r = 27 cm
Slant height = l = 10 cm
Surface area of the frustum
= πR2 + πr2 + πl (R + r)
= π [R2 + r2 + l (R+r)]
= [332 + 272 + 10(33 + 27)]π
= [1089 + 729 + 10(60)] π
= 2418 × 3.14
= 7592.52 cm2
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