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प्रश्न
The sum of three numbers is 58. The second number is three times of two-fifth of the first number and the third number is 6 less than the first number. Find the three numbers
उत्तर
Here what we know
a + b + c = 58 ...(sum of three numbers is 58)
Let the first number be ‘x’
b = a × 3 ...(the second number is three times of the first `2/5` number)
b = `3 xx 2/5x = 6/5x`
Third number = x – 6
Sum of the numbers is given as 58.
∴ `x + 6/5x + (x - 6)` = 58
Multiplying by 5 throughout, we ge
5 × x + 6x + 5 × (x – 6) = 58 × 5
5x + 6x + 5x – 30 = 290
∴ 16x = 290 + 30
∴ 16x = 320
∴ x = `320/16`
x = 20
1st number = 20
2nd number = `3 xx 2/5 xx 20 = 6/5 xx 20` = 24
3rd number = 24 – 16 = 14
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