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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

The unit cell of Na is bcc and its density is 0.97 g/cm3. What is the radius of a sodium atom if the molar mass of Na is 23 g/mol? - Chemistry

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प्रश्न

The unit cell of Na is bcc and its density is 0.97 g/cm3. What is the radius of a sodium atom if the molar mass of Na is 23 g/mol?

बेरीज

उत्तर

Given: Density = 0.97 g/cm3, Molar mass (M) = 23 g/mol

To find: Radius of sodium atom (r)

Formula:

1. Density (ρ) = `"M  n"/("a"^3  "N"_"A")`

2. For bcc unit cell, r = `(sqrt3  "a")/4`

Calculation: For a bcc lattice, number of atoms per unit cell is 2.

∴ n = 2

From formula (i),

`"a"^3 = "M  n"/(rho  "N"_"A")`

`"a"^3 = (23 "g mol"^-1 xx 2  "atom")/(0.97 "g cm"^-3 xx 6.022 xx 10^23 "atom  mol"^-1) = 7.875 xx 10^-23 "cm"^3`

a = `root(3)(7.875 xx 10^-23 "cm"^3) = 4.286 xx 10^-8`cm

From formula (ii),

r = `(sqrt3 "a")/4 = (sqrt3 xx 4.286 xx 10^-8)/4 = 1.86 xx 10^-8` cm

Radius of sodium atom is 1.86 × 10-8 cm.

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Crystal Structure
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