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प्रश्न
Three consecutive vertices of a parallelogram ABCD are A(S, 5), B(-7, -5) and C(-5, 5). Find the coordinates of the fourth vertex D.
उत्तर
we know that in a parallelogram diagonals bisect each other
∴ midpoint of AC = midpoint of BD
`"O" ((8 - 5)/2 , (5 + 5)/2) = "O"(("x" - 7)/2 , ("y" - 5)/2)`
`(8 - 5)/2 = ("x" - 7)/2 , (5 + 5)/2 = ("y" - 5)/2`
`3/2 = ("x" - 7)/2 , 10 = "y" - 5`
x = 10 , y = 15
Coordinates of fourth vertex D are (10 , 15)
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Find the midpoint of the line segment joining the following pair of point :
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Point P is the centre of the circle and AB is a diameter. Find the coordinates of points B if coordinates of point A and P are (2, – 3) and (– 2, 0) respectively.
Given: A`square` and P`square`. Let B (x, y)
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