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प्रश्न
Three moles of an ideal gas are expanded isothermally from 15 dm3 to 20 dm3 at a constant external pressure of 1.2 bar, calculate the amount of work in Joules.
उत्तर
Given: Initial volume (V1) = 15 dm3
Final volume (V2) = 20 dm3
External pressure (Pext) = 1.2 bar
To find: Amount of work in Joules
Formula: W = − Pext ΔV = − Pext (V2 − V1)
Calculation: From formula,
W = − Pext ΔV = − Pext (V2 − V1)
W = – 1.2 bar (20 dm3 − 15 dm3)
= – 1.2 bar × 5 dm3 = –6 dm3 bar
Now, 1 dm3 bar = 100 J
Hence, W = – 6 dm3 bar × `(100 "J")/(1 "dm"^3 "bar")` = - 600 J
The work done is – 600 J.
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