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Two parallel plates have a potential difference of 10 V between them. If the plates are 0.5 mm apart, what will be the strength of electric charge. - Physics

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प्रश्न

Two parallel plates have a potential difference of 10 V between them. If the plates are 0.5 mm apart, what will be the strength of electric charge.

संख्यात्मक

उत्तर

Given: V = 10 V, d = 0.5 mm = 0.5 × 10−3 m

To find: Strength of electric field (E)

Formula: E = Vd

Calculation: From the formula,

E = 100.5×10-3

= 20 × 103 V/m

The strength of the electric field will be 20 × 103 V/m

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पाठ 10: Electrostatics - Exercises [पृष्ठ २०६]

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बालभारती Physics [English] 11 Standard Maharashtra State Board
पाठ 10 Electrostatics
Exercises | Q 2. (iv) | पृष्ठ २०६

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