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Question
Two parallel plates have a potential difference of 10 V between them. If the plates are 0.5 mm apart, what will be the strength of electric charge.
Solution
Given: V = 10 V, d = 0.5 mm = 0.5 × 10−3 m
To find: Strength of electric field (E)
Formula: E = `"V"/"d"`
Calculation: From the formula,
E = `10/(0.5xx10^-3`
= 20 × 103 V/m
The strength of the electric field will be 20 × 103 V/m
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