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Chapters
2: Mathematical Methods
3: Motion in a Plane
4: Laws of Motion
5: Gravitation
6: Mechanical Properties of Solids
7: Thermal Properties of Matter
8: Sound
9: Optics
▶ 10: Electrostatics
11: Electric Current Through Conductors
12: Magnetism
13: Electromagnetic Waves and Communication System
14: Semiconductors
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Solutions for Chapter 10: Electrostatics
Below listed, you can find solutions for Chapter 10 of Maharashtra State Board Balbharati for Physics [English] 11 Standard Maharashtra State Board.
Balbharati solutions for Physics [English] 11 Standard Maharashtra State Board 10 Electrostatics Exercises [Pages 205 - 206]
Choose the correct option.
A positively charged glass rod is brought close to a metallic rod isolated from ground. The charge on the side of the metallic rod away from the glass rod will be ______.
same as that on the glass rod and equal in quantity
opposite to that on the glass of and equal in quantity
same as that on the glass rod but lesser in quantity
same as that on the glass rod but more in quantity
Choose the correct option.
An electron is placed between two parallel plates connected to a battery. If the battery is switched on, the electron will
be attracted to the +ve plate
be attracted to the -ve plate
remain stationary
will move parallel to the plates
Choose the correct option.
A charge of + 7 μC is placed at the centre of two concentric spheres with radius 2.0 cm and 4.0 cm respectively. The ratio of the flux through them will be
1:4
1:2
1:1
1:16
Choose the correct option.
Two charges of 1.0 C each are placed one meter apart in free space. The force between them will be
1.0N
9 × 109 N
9 × 10-9N
10N
Choose the correct option.
Two point charges of +5 μC are so placed that they experience a force of 8.0 × 10-3N. They are then moved apart so that the force is now 2.0 × 10-3N. The distance between them is now
`1/4` the previous distance
double the previous distance
four times the previous distance
half the previous distance
A metallic sphere A isolated from ground is charged to +50 μC. This sphere is brought in contact with other isolated metallics sphere B of half the radius of sphere A. The charge on the two-sphere will be now in the ratio
1 : 2
2 : 1
4 : 1
1 : 1
Choose the correct option.
Which of the following produces uniform electric field?
point charge
linear charge
two parallel plates
charge distributed an circular any
Choose the correct option.
Two-point charges of A = +5.0 μC and B = -5.0 μC are separated by 5.0 cm. A point charge C = 1.0 μC is placed at 3.0 cm away from the centre on the perpendicular bisector of the line joining the two point charges. The charge at C will experience a force directed towards
point A
point B
a direction parallel to line AB
a direction along the perpendicular bisector
Answer the following question.
What is the magnitude of the charge on an electron?
Answer the following question.
State the law of conservation of charge.
Define a unit charge.
Two parallel plates have a potential difference of 10 V between them. If the plates are 0.5 mm apart, what will be the strength of electric charge.
Answer the following question.
What is a uniform electric field?
Answer the following question.
If two lines of force intersect of one point. What does it mean?
Answer the following question.
State the units of linear charge density.
Answer the following question.
What is the unit of dipole moment?
Answer the following question.
What is relative permittivity?
Solve numerical examples.
Two small spheres 18 cm apart have equal negative charges and repel each other with the force of 6 × 10-3 N. Find the total charge on both spheres.
A charge +q exerts a force of magnitude -0.2 N on another change -2q. If they are separated by 25.0 cm, determine the value of q.
Two charges 5 μC and -4μC are kept 5.0 m apart at points A and B respectively. How much work will have to be done to move the charge at A through a distance of 5.0 m further away from point B along the line BA?
Solve numerical example.
Four charges of + 6×10-8 C each are placed at the corners of a square whose sides are 3 cm each. Calculate the resultant force on each charge and show in the direction and a diagram drawn to scale.
The electric field in a region is given by `vec"E"` = 5 `hatk`N/C. Calculate the electric flux Through a square of side 10.0 cm in the following cases
- The square is along the XY plane
- The square is along XZ plane
- The normal to the square makes an angle of 45° with the Z axis.
Solve numerical example.
Three equal charges of 10×10-8 C respectively, each located at the corners of a right triangle whose sides are 15 cm, 20 cm, and 25cm respectively. Find the force exerted on the charge located at the 90° angle.
Solve numerical example.
A potential difference of 5000 volts is applied between two parallel plates 5cm apart a small oil drop having a charge of 9.6 ×10-19 C falls between the plates. Find
- electric field intensity between the plates and
- the force on the oil drop.
Solve numerical example.
Calculate the electric field due to a charge of −8.0×10−8 C at a distance of 5.0 cm from it.
Solutions for 10: Electrostatics
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Balbharati solutions for Physics [English] 11 Standard Maharashtra State Board chapter 10 - Electrostatics
Shaalaa.com has the Maharashtra State Board Mathematics Physics [English] 11 Standard Maharashtra State Board Maharashtra State Board solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Balbharati solutions for Mathematics Physics [English] 11 Standard Maharashtra State Board Maharashtra State Board 10 (Electrostatics) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.
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Concepts covered in Physics [English] 11 Standard Maharashtra State Board chapter 10 Electrostatics are Introduction to Electrostatics, Electric Charges, Basic Properties of Electric Charge, Coulomb’s Law - Force Between Two Point Charges, Principle of Superposition, Electric Field, Electric Flux, Electric Dipole, Continuous Distribution of Charges, Gauss’s Law.
Using Balbharati Physics [English] 11 Standard Maharashtra State Board solutions Electrostatics exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Balbharati Solutions are essential questions that can be asked in the final exam. Maximum Maharashtra State Board Physics [English] 11 Standard Maharashtra State Board students prefer Balbharati Textbook Solutions to score more in exams.
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