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Question
Solve numerical example.
Calculate the electric field due to a charge of −8.0×10−8 C at a distance of 5.0 cm from it.
Solution
Given: q = −8.0×10−8 C, r = 5 cm = 5 × 10−2 m
To find: Electric field (E)
Formula: E = `1/(4πε_0)"q"/"r"^2`
Calculation: From formula,
E = `9xx10^9xx((-8xx10^-8))/(5xx10^-2)^2`
= −2.88 × 105 N/C
Electric field due to a charge is −2.88 × 105 N/C.
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