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प्रश्न
Use the method of monthly averages to find the monthly indices for the following data of production of a commodity for the years 2002, 2003 and 2004
2002 | 2003 | 2004 |
15 | 20 | 18 |
18 | 18 | 25 |
17 | 16 | 21 |
19 | 13 | 11 |
16 | 12 | 14 |
20 | 15 | 16 |
21 | 22 | 19 |
18 | 16 | 20 |
17 | 18 | 1 |
15 | 20 | 16 |
14 | 17 | 18 |
18 | 15 | 20 |
उत्तर
Computation of monthly indices for the production of a commodity using the method of monthly averages.
Months Years |
Jan | Feb | Mar | Apr | May | Jun | July | Aug | Sep | Oct | Nov | Dec |
2002 | 15 | 18 | 17 | 19 | 16 | 20 | 21 | 18 | 17 | 15 | 14 | 18 |
2003 | 20 | 1 | 16 | 13 | 12 | 15 | 22 | 16 | 18 | 20 | 17 | 15 |
2004 | 18 | 25 | 21 | 11 | 14 | 16 | 19 | 20 | 17 | 16 | 18 | 20 |
Monthly Total |
53 | 61 | 54 | 43 | 42 | 51 | 62 | 54 | 52 | 51 | 49 | 53 |
Monthly Average |
17.7 | 20.3 | 18 | 14.3 | 14 | 17 | 20.7 | 18 | 17.3 | 17 | 16.3 | 17.7 |
Seasonal Indices | 102 | 116.9 | 103.7 | 82.4 | 80.6 | 97.9 | 119.2 | 103.7 | 99.7 | 97.9 | 93.9 | 102 |
Grand Average = `("Sum of" 12 "Monthly Averages")/12`
= `(17.6 + 20.3 + 18 + 14.3 + 14 + 17 + 20.6 + 18 + 17.3 + 17 + 16.3 + 17.6)/12`
= `208/12`
= 17.33
S.I for January = `("Monthly Average" ("for Jan"))/"Grand Average" xx 100`
= `17.6/17.33 xx 100`
= `1760/17.33`
= 17.33
101.56
S.I for Febuary = `("Monthly Average" ("for Feb"))/"Grand Average" xx 100`
= `20.3/17.33 xx 100`
= `2030/17.33`
= 117.14
S.I for March = `("Monthly Average for March")/"Grand Average" xx 100`
= `18/17.33 xx 100`
= `1800/17.33`
= 103.86
S.I for April = `("Monthly Average for April")/"Grand Average" xx 100`
= `14.3/17.33 xx 100`
= `1430/17.3`
= 82.52
S.I for May = `("Monthly Average for May")/"Grand Average" xx 100`
= `14/17.33 xx 100`
= `1400/17.33`
= 80.78
S.I for June = `("Monthly Average for June")/"Grand Average" xx 100`
= `17/17.33 xx 100`
= `1700/17.33`
= 98.10
S.I for July = `("Monthly Average for July")/"Grand Average" xx 100`
= `20.6/17.33 xx 100`
= `2060/17.33`
= 118.87
S.I for August = `("Monthly Average for August")/"Grand Average" xx 100`
= `18/17.33 xx 100`
= `1800/17.33`
= 103.87
S.I for September = `("Monthly Average for September")/"Grand Average" xx 100`
= `17.3/17. xx 100`
= `1730/17.3`
= 100
S.I for October = `("Monthly Average for October")/"Grand Average" xx 100`
= `17/17.3 xx 100`
= `1700/17.33`
= 98.10
S.I for November = `("Monthly Average for November")/"Grand Average" xx 100`
= `16.3/17.33 xx 100`
= `1630/17.33`
= 94.06
S.I for December = `("Monthly Average for December")/"Grand Average" xx 100`
= `17.6/17.33 xx100`
= `1760/17.33`
= 101.56
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