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प्रश्न
What is the ratio in which the line segment joining (2, -3) and (5, 6) is divided by x-axis?
पर्याय
1:2
2:1
2:5
5:2
उत्तर
1:2
Explanation:
Let the line joining points A (2, -3) and B (5, 6) be divided by point P (x, 0) in the ratio k:1.
y = `(ky_2 + y_1)/(k + 1)`
0 = `(k xx 6 + 1 xx (-3))/(k + 1)`
0 = 6k – 3
k = `1/2`
Thus, the required ratio is 1:2.
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Complete the following activity to find the coordinates of point P which divides seg AB in the ratio 3:1 where A(4, – 3) and B(8, 5).
Activity:
∴ By section formula,
∴ x = `("m"x_2 + "n"x_1)/square`,
∴ x = `(3 xx 8 + 1 xx 4)/(3 + 1)`,
= `(square + 4)/4`,
∴ x = `square`,
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∴ y = `square`
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