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प्रश्न
What is the total number of sigma and pi bonds in the following molecules?
C2H2
उत्तर १
A single bond is a result of the axial overlap of bonding orbitals. Hence, it contributes a sigma bond. Multiple bonds (double or triple bonds) are always formed as a result of the sidewise overlap of orbitals. A pi-bond is always present in it. A triple bond is a combination of two pi-bonds and one sigma bond.
The structure of C2H2 can be represented as:
Hence, there are three sigma and two pi-bonds in C2H2.
उत्तर २
H—C = C—H
Sigma bond = 3
π bonds = 2
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\[\begin{array}{cc}
\phantom{.....}\ce{O}\\
\phantom{.....}||\\
\ce{\overset{∗}{C}H2 = CH - \overset{∗}{C} - O - H}
\end{array}\]
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\[\begin{array}{cc}
\phantom{..........}\ce{O}\\
\phantom{..........}||\\
\ce{CH3 - CH2 - \overset{∗}{C} - H}
\end{array}\]
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