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प्रश्न
उत्तर
Let m be the mass of liquid A.
Assuming that there is no heat loss,
Heat energy given by A = Heat energy taken by B
or, m x 0.84 x ( 40 - 32) = 100 x 2.1 x ( 32 - 20)
or, m = `(100 xx 2.1 xx 12)/(0.84 xx 8)` = 375 g
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