Advertisements
Advertisements
प्रश्न
Which acid of the pair shown here would you expect to be stronger?
उत्तर
|
−CF3 has a strong −I effect, stabilising the carboxylate ion by dispersing the negative charge. |
−CF3 has weak +I effect, it destabilises the carboxylate ion by condensing the negative charge. |
Therefore, F3C–C6H4–COO– (p) ion is more stable than CH3–C6H4COO– (p) ion because of F3C–C6H4–COO– (p) ion.
APPEARS IN
संबंधित प्रश्न
How is 1-nitropropane prepared from suitable oxime?
Although phenoxide ion has more number of resonating structures than carboxylate ion, carboxylic acid is a stronger acid than phenol. Give two reasons.
Why pKa of F-CH2-COOH is lower than that of Cl−CH2−COOH?
CH3CO2H or CH2FCO2H
Which acid of the pair shown here would you expect to be stronger?
CH2FCO2H or CH2ClCO2H
Arrange the following compounds in increasing order of their property as indicated:
CH3CH2CH(Br)COOH, CH3CH(Br)CH2COOH, (CH3)2CHCOOH, CH3CH2CH2COOH (acid strength)
Arrange the following compounds in increasing order of their property as indicated:
Benzoic acid, 4-Nitrobenzoic acid, 3, 4-Dinitrobenzoic acid, 4-Methoxybenzoic acid (acid strength)
Write the reactions involved Hell-Volhard Zelinsky reaction?
Account for the following:
Carboxylic acid is a stronger acid than phenol.
What happens when Salicylic acid is treated with (CH3CO)2 O/H+?
Arrange the following compounds in increasing order of their property as indicated:
F - CH2COOH, O2N - CH2 COOH CH3 COOH,HCOOH - acid character.
Complete the following reaction sequence.
\[\begin{array}{cc}
\ce{O}\phantom{...............................................}\\
||\phantom{...............................................}\\
\ce{CH3 - C - CH3 ->[(i) CH3MgBr][H2O] (A) ->[Na metal][Ether] (B) ->[CH3 - Br] (C)}
\end{array}\]
When propionamide reacts with Br2 in the presence of alkali the product is ______.
Na2CO3 cannot be used in place of (NH4)2CO3 for the precipitation of the V group because ______.
Formic acid and formaldehyde can be distinguished by treating with ______.
Describe the action of alcoholic potassium hydroxide (alc. KOH) on isopropyl bromide.
