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प्रश्न
Which of the following ions is more stable? Use resonance to explain your answer.
उत्तर
Structure (A) is more stable due to resonance. Structure (B) is non-planar and hence it does not undergo resonance. Double bond is more stable within the ring in comparison to outside the ring.
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संबंधित प्रश्न
Draw the resonance structure for the following compound. Show the electron shift using curved-arrow notation.
CH3CH = CHCHO
Draw the resonance structure for the following compound. Show the electron shift using curved-arrow notation.
C6H5 – CHO
Draw the resonance structure for the following compound. Show the electron shift using curved-arrow notation.
\[\ce{CH3CH = CH\overset{+}{C}H2}\]
What is the hybridisation of each carbon in H2C = C = CH2.
Draw the possible resonance structures for \[\ce{CH3 - \overset{\bullet\bullet}{\underset{\bullet\bullet}{O}} - \overset{+}{C}H2}\] and predict which of the structures is more stable. Give reason for your answer.
The structure of triphenylmethyl cation is given below. This is very stable and some of its salts can be stored for months. Explain the cause of high stability of this cation.
Draw the resonance structure of the following compounds;
CH2 = CH – CH = CH2
Draw the resonance structure of the following compounds;
\[\begin{array}{cc}
\ce{CH2 = CH - C = O}\\
\phantom{.........}|\\
\phantom{.........}\ce{H}
\end{array}\]
Which of the two structures (A) and (B) given below is more stabilised by resonance? Explain.
\[\ce{\underset{(A)}{CH3COOH}}\] and \[\ce{\underset{(B)}{CH3CO\overset{Θ}{O}}}\]
Assertion (A): Energy of resonance hybrid is equal to the average of energies of all canonical forms.
Reason (R): Resonance hybrid cannot be presented by a single structure.
