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प्रश्न
Which one of the points 10 – 8i, 11 + 6i is closest to 1 + i
उत्तर
A(1 + i)
B(10 – 8i)
C(11 + 6i)
|AB| = |(10 – 8i) – (1 + i)|
= |10 – 8i – 1 – i|
= |9 – 9i|
= `sqrt(81 + 81)`
= `sqrt(162)`
= 9(1.414)
= 12.726
CA = |(11 + 6i) – (1 + i)|
= |11 + 6i – 1 – i|
= |10 + 5i|
= `sqrt(100 + 25)`
= `sqrt(125)`
C(11 + 6i) is closest to the point A(1 + i)
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