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X5-cosxsinx - Mathematics

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प्रश्न

`(x^5 - cosx)/sinx`

बेरीज

उत्तर

`d/(dx) ((x^5 - cos x)/sinx) = (sin x * d/(dx) (x^5 - cos x) - (x^5 - cos x) * d/(dx) (sin x))/(sin^2x)`

= `(sin x(5x^4 + sin x) - (x^5 - cos x)(cosx))/(sin^2x)`  ....[Using quotient rule]

= `(5x^4 * sin x + sin^2x - x^5 cos x + cos^2x)/(sin^2x)`  

= `(5x^4 sinx - x^5 cosx + (sin^2x + cos^2x))/(sin^2x)`

= `(5x^4 sin x - x^5 cos x + 1)/(sin^2x)`

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पाठ 13: Limits and Derivatives - Exercise [पृष्ठ २४१]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
पाठ 13 Limits and Derivatives
Exercise | Q 34 | पृष्ठ २४१

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