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Question
`16/x-1=15/(x+1),x≠0,-1`
Solution
`16/x-1=15/(x+1),x≠0,-1`
⇒ `16/x-15/(x+1)=1`
⇒ `(16x+16-15x)/(x(x+1))=1`
⇒ `(x+16)/(x^2+x)=1`
⇒`x^2+x=x+16` (Cross multiplication)
⇒`x^2-16=0`
⇒`(x+4) (x-4)=0`
⇒`x+4=0 or x-4=0`
⇒`x=-4 or x=4`
Hence, -4 and 4 are the roots of the given equation.
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