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Maharashtra State BoardSSC (English Medium) 9th Standard

2 tan 45° + cos 45° − sin 45° = ? - Geometry

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Question

2 tan 45° + cos 45° − sin 45° = ?

Options

  • 0

  • 1

  • 2

  • 3

MCQ

Solution

2

Explanation:

2 tan 45° + cos 45° − sin 45°

= `2 xx 1 + 1/sqrt2 - 1/sqrt2`

= `2 + (1 - 1)/sqrt2`

= `2 + (0)/sqrt2`

= 2

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Trigonometric Ratios of 30° and 60° Angles
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Chapter 8: Trigonometry - Problem Set 8 [Page 113]

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Balbharati Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board
Chapter 8 Trigonometry
Problem Set 8 | Q 1. (iii) | Page 113
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