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![Balbharati solutions for Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board chapter 8 - Trigonometry - Shaalaa.com](/images/geometry-mathematics-2-english-9-standard-maharashtra-state-board_6:0e8db292b5c64d6e8d65b3ca4a58b2d7.jpg "Balbharati solutions for Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board chapter 8 - Trigonometry")
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Solutions for Chapter 8: Trigonometry
Below listed, you can find solutions for Chapter 8 of Maharashtra State Board Balbharati for Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board.
Balbharati solutions for Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board 8 Trigonometry Practice Set 8.1 [Page 104]
In the given Figure, ∠R is the right angle of ΔPQR. Write the following ratios.
- sin P
- cos Q
- tan P
- tan Q
In the right angled Δ XYZ, ∠XYZ = 90° and a, b, c are the lengths of the sides as shown in the figure. Write the following ratios,
- sin X
- tan Z
- cos X
- tan X.
In right angled ΔLMN, ∠LMN = 90°, ∠L = 50° and ∠N = 40°, write the following ratios.
- sin 50°
- cos 50°
- tan 40°
- cos 40°
In the given figure, ∠PQR = 90°, ∠PQS = 90°, ∠PRQ = α and ∠QPS = θ Write the following trigonometric ratios.
- sin α, cos α, tan α
- sin θ, cos θ, tan θ
Balbharati solutions for Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board 8 Trigonometry Practice Set 8.2 [Page 112]
In the following table, a ratio is given in each column. Find the remaining two ratios in the column and complete the table.
| sin θ | `11/61` | `1/2` | `3/5` | ||||||
| cos θ | `35/37` | `1/sqrt3` | |||||||
| tan θ | `1` | `21/20` | `8/15` | `1/(2sqrt2)` |
Find the values of -
5 sin 30° + 3 tan 45°
Find the values of -
`4/5` tan2 60° + 3sin2 60°
Find the values of -
2 sin 30° + cos 0° + 3 sin 90°
Find the values of -
`[tan 60°]/[sin 60° + cos 60°]`
Find the values of -
cos2 45° + sin2 30°
Find the values of -
cos 60° × cos 30° + sin 60° × sin 30°
If sin θ = `4/5` then find cos θ.
If cos θ = `15/17` then find sin θ.
Balbharati solutions for Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board 8 Trigonometry Problem Set 8 [Page 113]
Choose the correct alternative answer for following multiple choice questions.
Which of the following statements is true?
sin θ = cos (90 - θ)
cos θ = tan (90 - θ)
sin θ = tan (90 - θ)
tan θ = tan (90 - θ)
Which of the following is the value of sin 90°?
`sqrt 3/2`
0
`1/2`
1
2 tan 45° + cos 45° − sin 45° = ?
0
1
2
3
`(cos 28°)/(sin 62°)` = ?
2
-1
0
1
In right angled ΔTSU, TS = 5, ∠S = 90°, SU = 12 then find sin T, cos T, tan T. Similarly find sin U, cos U, tan U.
In right angled ΔYXZ, ∠X = 90°, XZ = 8 cm, YZ = 17 cm, find sin Y, cos Y, tan Y, sin Z, cos Z, tan Z.
In right angled ΔLMN, if ∠N =θ, ∠M = 90, cos θ =`24/25`, find sin θ and tan θ Similarly, find (sin2 θ) and (cos2 θ).
Fill in the blanks.
sin20° = cos ______°
tan 30° × tan ______° = 1
cos 40° = sin ______°
Solutions for 8: Trigonometry
Balbharati solutions for Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board chapter 8 - Trigonometry
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Concepts covered in Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board chapter 8 Trigonometry are Trigonometry, Terms Related to Right Angled Triangle, Trigonometric Table, Trigonometric Ratios and Its Reciprocal, Trigonometric Ratios of 30° and 60° Angles, Important Equation in Trigonometry, Relation Among Trigonometric Ratios.
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