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Question
In the given figure, ∠PQR = 90°, ∠PQS = 90°, ∠PRQ = α and ∠QPS = θ Write the following trigonometric ratios.
- sin α, cos α, tan α
- sin θ, cos θ, tan θ
Solution
(i) In ∆PQR,
sin α = `"Opposite Side Of ∠PRQ"/"Hypotenuse"= "PQ"/"PR"`
cos α = `"Adjacent side of ∠PRQ"/"Hypotenuse" = "RQ"/"PR"`
tan α = `"Opposite side of ∠PRQ"/"Adjacent side of ∠PRQ" = "PQ"/"RQ"`
(ii) In ∆PQS,
sin θ = `"Opposite Side Of θ "/"Hypotenuse" = "QS"/"PS"`
cos θ = `"Adjacent side of θ"/"Hypotenuse" = "PQ"/"PS"`
tan θ = `"Opposite side of θ"/"Adjacent side of θ" = "QS"/"PQ"`
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