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Question
In the given Figure, ∠R is the right angle of ΔPQR. Write the following ratios.
- sin P
- cos Q
- tan P
- tan Q
Solution
(i) sin P = `"Opposite side of ∠P"/"Hypotenuse" = "QR"/"PQ"`
(ii) cos Q = `"Adjacent side of ∠Q"/"Hypotenuse" = "QR"/"PQ"`
(iii) tan P = `"Opposite side of ∠P"/"Adjacent side of ∠P" = "QR"/"PR"`
(iv) tan Q = `"Opposite side of ∠Q"/"Adjacent side of ∠Q" = "PR "/"QR"`
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