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Maharashtra State BoardSSC (English Medium) 9th Standard

In right angled ΔYXZ, ∠X = 90°, XZ = 8 cm, YZ = 17 cm, find sin Y, cos Y, tan Y, sin Z, cos Z, tan Z. - Geometry

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Question

In right angled ΔYXZ, ∠X = 90°, XZ = 8 cm, YZ = 17 cm, find sin Y, cos Y, tan Y, sin Z, cos Z, tan Z.

Sum

Solution

In right ∆YXZ,

YZ2 = XZ2 + XY2           ...(Pythagoras theorem)

⇒ XY2 = YZ2 − XZ2

⇒ XY2 = 172 − 82 

⇒ XY2 = 289 − 64

⇒ XY2 = 225

⇒ XY2 = 152

∴  XY = 15 cm

Now,

sin Y = `("∠Y"  "opposite side")/"Hypotenuse" =  "XZ"/"YZ" = 8/17`

cos Y = `("∠Y"  "adjacent side")/"Hypotenuse" = "XY"/"YZ" = 15/17`

tan Y = `("∠Y"  "opposite side")/("∠Y"  "adjacent side") = "XZ"/"XY" = 8/15`

Also,

sin Z = `("∠Z"  "opposite side")/"Hypotenuse" = "XY"/"YZ" = 15/17`

cos Z = `("∠Z"  "adjacent side")/"Hypotenuse" = "XZ"/"YZ" = 8/17`

tan Z = `("∠Z"  "opposite side")/("∠Z"  "adjacent side") = "XY"/"XZ" = 15/8`

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Chapter 8: Trigonometry - Problem Set 8 [Page 113]

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