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Maharashtra State BoardSSC (English Medium) 9th Standard

Cos28°sin62° = ? - Geometry

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Question

`(cos 28°)/(sin 62°)` = ?

Options

  • 2

  • -1

  • 0

  • 1

MCQ

Solution

1

Explanation:

`[cos 28°]/[sin 62°]`

= `[sin( 90°- 28°)]/(sin 62°)`     ...[cos θ = sin(90°- θ)]

= `[sin 62°]/[sin 62°]`   

= 1

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Chapter 8: Trigonometry - Problem Set 8 [Page 113]

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Balbharati Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board
Chapter 8 Trigonometry
Problem Set 8 | Q 1. (iv) | Page 113
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