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प्रश्न
`(cos 28°)/(sin 62°)` = ?
विकल्प
2
-1
0
1
उत्तर
1
Explanation:
`[cos 28°]/[sin 62°]`
= `[sin( 90°- 28°)]/(sin 62°)` ...[cos θ = sin(90°- θ)]
= `[sin 62°]/[sin 62°]`
= 1
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